Singularities

Poles of Order 2

Function 1/(1–z)²

The function \dfrac{1}{(1-z)^2} \; (z\in\mathbb{C}) has one pole of order 2 at z=1 .
Its finite value at its pole z=1 is:

\dfrac{1}{(1-1)^2} = -\dfrac{1}{12}

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